Pbiet Ip=(Mp1q1)/(Mp0q1)
Pbiet Ip=(Mp1q1)/(Mp0q1) v Iq=(Mp0q1)/(Mp0q0)
giong
-deu la chi so lien hop fanh sub dong chung of tung ki ngcuu so voi ki goc
Khac
-1 la chi so lien hop ve gia ca,2 ve sluong
-quyen so of 1 la q1,cua 2 la p0
-1 ngcuu sub dong of gia ca cac mat hag noi chuhng ki ngcuu so voi ki goc
2 ngcuu sub dong sub dong of luong hag hoanoi chug ki ngcuu so voi ki goc
-y nghia kte(khi lay luong tag,giam tuyet doi)
(1) la luong $ngmua fai bo them(neu gia tag)hay tiet keim dc(neu gia giam)de mua cung khluong h2 tren thuc te hoac tu ct1 cho ta biet voi cung 1 luong h2 tieu dung nhu thuc te,khi gia thdoi,thi ho se tiet kiem,boi chio ki ngcuu 1 khoan bnhieu
(2) la luong $ ng mua hag fai bo them (khi luong h2 tag) hay nguoc lai de mua hag voi cung 1 muc gia cdinh o ky goc hoac khi kluong h2 thdoi voi cung 1 muc giacdinh o ki gocthi ho se tiet kiem,bchi 1 khoan bnhieu
Mqhe
Ip x Iq fan anh sub dong of tong muc tieu thu(tog gia ca,ton gdoah thu) o ki ngcuu so voi ki goc
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